Question

If x=3 and yz=x and z-y=1 find y and z

Answer 1

From first two equations, we have
yz=3
y(y+1)=3
y^2 + y-3=0
using shredharacharya's formula
y= {-1+-root(13)} /2
substituting y in the third equation, we get
z= {1+-root(13)} /2

Answer 2

x=3
. ˙ .yz=3
y=3/z
z-y =1
z-3/z=1
sq.z -3=z
sq.z-z-3=0
by using quadratic equation formula:
z=(1+√13)/2, (1-√13)/2
. ˙.y=(-1+√13)/2 , (-1-√13)/2