Question

If x^3 +ax^2 +bx +6 has x-2 as a factor and leaves a remainder 3, when divided by x-3, find the values of a and b.
Ans(a= -3, b= -1)
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Answer 1

Answer:

Step-by-step explanation:

g[x]=2 because

x-2=0 therefore x=2

p[x]=x^3+ax^2+bx+6

p[2]=2^3+a2^2+2b+6

      =8+4a+2b+6