If x^3+ax^2+bx+6 has x-2 as a factor and leaves a remainder 3 when divided by x-3 , find the values of a and b
Answers
Answered by
0
Step-by-step explanation:
By using remainder theorem,
we get,
3a+b=-10
2a+b=-7
Solving these,
a=-3,b=-1
Similar questions