If (x+3) divides p(x)=x^3+4x^2+7 and q(x) =x^2-4x+a the remainder in each case is same find the value of a
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Answer: a = 21
Step-by-step explanation:
The question says that (x+3) divides p(x) and q(x) leaving same remainders.
Therefore (x+3) = 0
x = -3.
Substitue value of x in g(x)
g(3) = (-3)^2 - 4(-3) + a = 0
9 + 12 + a = 0
21 + a = 0
a = -21.
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