If x= 3, find the value of (*13+x-13) (x2/3
+ x -2/3 – 1)
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x+1x=−−√ 13
(x+1x)2=(13−−√)2
x2+1x2=13−2=11(1)
(x−1x)2=x2+1x2−2=11−2=9
x−1x=±3(2)
(x−1x)3=(±3)3
x3−1x3−3(x−1x)=±27
x3−1x3=±27+(3)(±3)=±36(3)
(x3−1x3)(x2+1x2)=(±36)(11)
x5−1x5+(x−1x)=±396
x5−1x5=±396∓3
x5−1x5=±393
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