if x= 3 find the value of K ::: x^2-2kx-6=0
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Answered by
2
Hi friend
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Your answer
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Given that : - x = 3.
To calculate : - value of k.
Now,
----------
Let , p(x) = x² - 2kx - 6 = 0
Then,
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p(3) = (3)² - 2 × k × 3 - 6 = 0
=> 9 - 6k - 6 = 0
=> 3 - 6k = 0
=> - 6k = - 3
=> k = - 3/- 6
=> k = 1/2
HOPE IT HELPS
--------------
Your answer
--------------------
Given that : - x = 3.
To calculate : - value of k.
Now,
----------
Let , p(x) = x² - 2kx - 6 = 0
Then,
-----------
p(3) = (3)² - 2 × k × 3 - 6 = 0
=> 9 - 6k - 6 = 0
=> 3 - 6k = 0
=> - 6k = - 3
=> k = - 3/- 6
=> k = 1/2
HOPE IT HELPS
Answered by
1
x^2-2kx-6=0
=>3^2-2×k×3-6=0
=>9-6k-6=0
=>3-6k=0
=>3=6k
=>k=3/6
=>k=1/2
=>3^2-2×k×3-6=0
=>9-6k-6=0
=>3-6k=0
=>3=6k
=>k=3/6
=>k=1/2
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