if x=3 is 1 root of number quadratic equation x^2-2kx-6=0. find the value of k
Answers
Answered by
2
p (x) = x^2 -2kx - 6 =0
p (3) = (3)^2 - 2 k (3) - 6 = 0
9 - 6k - 6 =o
-6k + 3 = 0
3 = 6k
3/6= k => 1/2 = k
HOPE IT HELPS YOU
ALL THE BEST FOR YOUR EXAM ☆ ☆
p (3) = (3)^2 - 2 k (3) - 6 = 0
9 - 6k - 6 =o
-6k + 3 = 0
3 = 6k
3/6= k => 1/2 = k
HOPE IT HELPS YOU
ALL THE BEST FOR YOUR EXAM ☆ ☆
Similar questions