Math, asked by vaishnavigoud, 3 months ago

if x-3 is a factor of 2x³-x²+kx+6 then find the value of k.​

Answers

Answered by BrainlyUser003
1

The answer is K=13

Step-by-step explanation:

P(3) = 2(3)³-(3)²-k(3) -6

P(3) = 2(27) - 9 -k(3) -6

P(3) = 54 -9 -k(3) -6

54 - 9 - 6= 39

39/3=k(3)/3

k=13

P(3) = 54 - 9 - 13(3) -6

P(3) = 54- 9 - 39 - 6

P(3) = 0

Therefore, the value of k is equal to 13; and x-3 is a factor

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