if x-3 is a factor of 2x³-x²+kx+6 then find the value of k.
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The answer is K=13
Step-by-step explanation:
P(3) = 2(3)³-(3)²-k(3) -6
P(3) = 2(27) - 9 -k(3) -6
P(3) = 54 -9 -k(3) -6
54 - 9 - 6= 39
39/3=k(3)/3
k=13
P(3) = 54 - 9 - 13(3) -6
P(3) = 54- 9 - 39 - 6
P(3) = 0
Therefore, the value of k is equal to 13; and x-3 is a factor
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