Question

If (x-3) is a factor of
(mx³ – x²– 45) , then find the value of m.​

Answer 1

Answer:

Explanation:

Let

f

(

x

)

=

x

3

−

6

x

2

+

k

x

+

10

If

(

x

+

2

)

is a factor

Then,

f

(

−

2

)

=

0

f

(

−

2

)

=

−

8

−

24

−

2

k

+

10

=

0

2

k

=

−

22

k

=

−

11

Answer 2

Answer:

$(x-3) is a factor of </p><p>(mx³ – x²– 45) \\ we \: know \\ infactor \: theorem \: \\ f(x) = 0 \\ f(3) =(m3³ – 3²– 45) = 0 \\ \: m27 - 9 - 45 = 0 \\ 27m = 54 \\ m = 54 \div 27 \\ therefore \: m = 2$

.......hope... it ....helps.......uu.........