If (x-3) is a factor of P(x)
=x²-mx²+ (m +1) X-12, find the
3
value of 'm'
Answers
Answered by
1
Answer:
m=0
Step-by-step explanation:
(3)^2-m(3)^2+(m+1)3-12=0
9-9m+(m+1)-9=0
9-9m-9m-9=0
-18m=0
m=0/(-18)
m=0
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