Question

if (x-3)is a factor of p(x)=x³-mx²+(m+1) x-12,find the value of m ​

Answer 1

$\large\bf\underline\pink{Given:-}$

(x-3)is a factor of p(x)=x³-mx²+(m+1) x-12

$\large\bf\underline\pink{To\:Find:-}$

Value of 'm'

$\large\bf\underline\pink{Solution:-}$

Put x = 3 in p(x)

p(3) = (3)³ - m(3)² + (m + 1) × 3 - 12

= 27 - 9m + 3m + 3 - 12

= 18 - 6m

- 6m = - 18

m = - 18 /- 6

m = 3

PLEASE MARK IT BRAINILIEST

Answer 2

Answer:

m= 3

Step-by-step explanation:

x-3 is a factor so its root is x=3

put this value of x in the given polynomial

(3)³- m(3)²+(m+1)3 -12 = 0

27-9m+3m+3-12 = 0

18-6m =0

18=6m

m=3