Question

If(x-3) is a factor of p(x) = xxx - kxx+ (k + 1)x - 12, find the value of k.​

Answer 1

Step-by-step explanation:

factor of P(x)=(x-3)

there fore zero is 3

put x=3 and P(x) =0

3×3×3 -k×3×3+(k+1)3-12=0

27 -9K -9K-9=0

18 -18K=0

18=18K

18/18 =K

K=1

value of K is 1

hope it will help you

follow me

make it BRIANLIEST

Answer 2

The value of k is 6.

Step-by-step explanation:

The given polynomial is

$p(x)=x^3-kx^2+(k+1)x-12$

Since, (x-3) is a factor of p(x). Hence, x = 3 must be a zero of this polynomial.

So, if x = 3 is a zero of p(x) then, we have

p(3) = 0

$3^3-k(3)^2+(k+1)3-12=0\\\\27-9k+3k+3-12=0\\\\-3k+18=0\\\\3k=18\\\\k=6$

Therefore, the value of k is 6.

#Learn More:

Find the value of k for which one root of the quadratic equation kxX-14x+8=0 is 2

https://brainly.in/question/7129149