If (x+3) is a factor of polynomial x^3+2x^2-mx-18,then the value of m is ?
Answers
Answered by
3
Answer:
m=9
Step-by-step explanation:
p(x)=x^3+2x^2-mx-18
x+3=0
x=-3
p(-3)=0
(-3)^3+2*(-3)^2-m(-3)-18=0
-27+2*9+3m-18=0
-27+18+3m-18=0
3m-27=0
3m=27
m=9
Similar questions
Accountancy,
5 months ago
Computer Science,
5 months ago
Math,
9 months ago
History,
9 months ago
Psychology,
1 year ago