Math, asked by akandaj12, 9 months ago

If (x+3) is a factor of polynomial x^3+2x^2-mx-18,then the value of m is ?​

Answers

Answered by pratham280604
3

Answer:

m=9

Step-by-step explanation:

p(x)=x^3+2x^2-mx-18

x+3=0

x=-3

p(-3)=0

(-3)^3+2*(-3)^2-m(-3)-18=0

-27+2*9+3m-18=0

-27+18+3m-18=0

3m-27=0

3m=27

m=9

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