if X+3 is a factor of polynomial x^3+7kx^2-2(kx+9k). find others zeroes also
Answers
Answered by
0
Answer:
x=(-3)
Explanation:
x+3=0
x=(-3)
x^3+7kx^2-2(kx+9k)
0=(-3)^3 +7×k×(-3)^2 -(2kx+18k)
0=(-27)+(7×k×9)-[{2×k×(-3)}+18k]
0=(-27)+63k -(-6k)+18k
0=(-27)+63k+6k+18k
0=(-27)+(87k)
0+27=87k
27/87 = k
9/29=k answer.
Answered by
0
Answer:
k = 9/17
Explanation:
If (x+3) is the factor of given polynomial, then x = - 3 is the zero of the polynomial.
In that case, (- 3)³ + 7k(-3)² - 2[k(-3) + 9k] = 0
- 27 + 63k + 6k - 18k = 0
- 27 + 51k = 0
51k = 27 ⇒ 17k = 9
k =
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