Question

if X+3 is a factor of polynomial x^3+7kx^2-2(kx+9k). find others zeroes also​

Answer 1

Answer:

x=(-3)

Explanation:

x+3=0

x=(-3)

x^3+7kx^2-2(kx+9k)

0=(-3)^3 +7×k×(-3)^2 -(2kx+18k)

0=(-27)+(7×k×9)-[{2×k×(-3)}+18k]

0=(-27)+63k -(-6k)+18k

0=(-27)+63k+6k+18k

0=(-27)+(87k)

0+27=87k

27/87 = k

9/29=k answer.

Answer 2

Answer:

k = 9/17

Explanation:

If (x+3) is the factor of given polynomial, then x = - 3 is the zero of the polynomial.

In that case, (- 3)³ + 7k(-3)² - 2[k(-3) + 9k] = 0

- 27 + 63k + 6k - 18k = 0

- 27 + 51k = 0

51k = 27 ⇒ 17k = 9

k = $\frac{9}{17}$