if x-3 is a factor of x^2-6x+12, then find the value of k. also find the other factor of the -polynomial for this value of k.
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Let f(x)=4x
3
+3x
2
−4x+k.
⇒(x−2) is a factor of f(x)
⇒ Remainder=0
⇒f(2)=4(2)
3
+3(2)
2
−4×(2)+k=0
⇒32+12−8+k=0
⇒36+k=0
∴k=−36
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Answered by
2
Step-by-step explanation:
there is mistake in question in the place of 6x there is Kx.
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