If (x+3) is a factor of x^3+ax^2-bx+6 and a+b=7 find the values of a and b
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x+3
x=-3
p(-3)=(-3)^3+a(-3)^2-b(-3)+6
=-27+9a+3b+6
9a+3b-21
9(7-b)+3b-21
63-9b+3b-21
-3b+42=0
b=-42/-3=14
a=7-b
a=7-14=-7
x=-3
p(-3)=(-3)^3+a(-3)^2-b(-3)+6
=-27+9a+3b+6
9a+3b-21
9(7-b)+3b-21
63-9b+3b-21
-3b+42=0
b=-42/-3=14
a=7-b
a=7-14=-7
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