Question

if (x-3) is a factor of x^3-mx^2+6x-18 then find the value of m​

Answer 1

Answer:

x-3=0(factor theorem)

x=3

putting value of x in equation

3^3-m(3)^2+6(3)-18=0

27-9m+18-18=0

27-9m=0

27=9m

27/9=m

m=3

Answer 2

Answer:

(x-3)=0

x=3

P(x)=x³-mx²+6x-18

P(3)=3³-m×3²+6×3-18

=27-9m+18-18

=27-9m

27-9m=0

27=9m

m = 3