Question

If (x-3) is a factor of x-5x2+6x+20p, then the value of p is:​

Answer 1

x-3=0

x=3

x=x-5x^2+6x+20p

x(3) =3-5(3) ^2+6(2) +20p=0

=3-5(9) +12+20p=0

=3-45+12+20p=0

=-42+12+20p=0

=12+20p=42

=20p=42-12

=20p=30

=p=30/20

=p=3/2

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