Question

if x+3 is a factor of x cube + 7x square +16x + a then the value of the a​

Answer 1

Answer:

12=a

Step-by-step explanation:

x+3 us a factor of p(z): x^3+7x^2+16x+a

therefore X = -3

substitute X in p(z)

=-27+63-48+a = 0 (as x-3 is a factor)

=a-12 =0

a = 12

Answer 2

Answer:

a=12

Step-by-step explanation:

x^3+7x^2+16x+a

given

x+3=0

x=-3

put the value of x in the above equation

,(-3^3)+7*(-3^2)+16*-3+a=0

-27+7*9-48+a=0

-27+63-48+a=0

36-48+a=0

-12+a=0

a=12

hope it helps