if x+3 is a factor of x cube + 7x square +16x + a then the value of the a
Answers
Answered by
1
Answer:
12=a
Step-by-step explanation:
x+3 us a factor of p(z): x^3+7x^2+16x+a
therefore X = -3
substitute X in p(z)
=-27+63-48+a = 0 (as x-3 is a factor)
=a-12 =0
a = 12
Answered by
1
Answer:
a=12
Step-by-step explanation:
x^3+7x^2+16x+a
given
x+3=0
x=-3
put the value of x in the above equation
,(-3^3)+7*(-3^2)+16*-3+a=0
-27+7*9-48+a=0
-27+63-48+a=0
36-48+a=0
-12+a=0
a=12
hope it helps
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