if (x-3) is a factor of x2-2x-15, then the other factor is __( ) a) (x-5) b) (x+5) c) (x-2) d) (x+2)
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2
Answer:
Let (x−a) be the other factor.
Now, (x+5),(x−a) are factors of the quadratic equation x
2
+x−20
Thus,
(x+5)(x−a)=x
2
+x−20
=>x
2
−ax+5x−5a=x
2
+x−20
=>x(5−a)−5a=x−20
Now, considering the co-efficients of x on the both sides,
5−a=1
=>a=5−1=4
Therefore the other factor is (x−4)
Step-by-step explanation:
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(x-5)
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