Question

If (x-3) is a factor of x²−Kx-15 is divisible by then K=?

Answer 1

Answer:

x-3=0{we need to find the zero of the polynomial}

therefore,x=3,

now putting x=3 in p(x)=x2-kx-15,

we have: (3)2 -3.k -15=0{by factor theorem}

thus, 9-3k-15=0

or, -6-3k=0

=> k= -2

Answer 2

Answer:

✒ Given polynomial p(x) = x² - kx - 15 = 0

✒ (x - 3) is a factor of p(x)

• x - 3 = 0
• x = 0 + 3
• x = 3

Substitute the value of x in p(x)

➡ (3)² -k(3) - 15 = 0

➡ 9 - 3k - 15 = 0

➡ - 3k - 6 = 0

➡ - 3k = 0 + 6

➡ - 3k = 6

➡ k = 6/(-3)

➡ k = - 2

Hence, the value of k is “ -2 ”

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Explanation:

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