If x=3 is A root of the equation x²+px-15=0, value of p is
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Answered by
1
Answer:
Since −5 is a root of the equation 2x
2
+px−15=0. Therefore,
2(−5)
2
−5p−15=0⇒p=7
Putting p=7 in p(x
2
+x)+k=0 we get
7x
2
+7x+k=0
Here ,a=7,b=7;c=k
This equation will have equal roots, if
Discriminant =b
2
−4ac=0 ⇒49−4×7×k=0⇒k=
28
49
⇒k=
4
7
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Answered by
0
Answer:
22
Step-by-step explanation:
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