If x 3
is a solution of a quadratic equation x
2kx60, then find the value of k.
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Since the sign between the variables isn't visible ,
the possible values of k are
k=-5. if x²+kx+6=0
k=-1 if x²+kx-6=0
k=5 if x²-kx+6=0
k=1 if x²-kx-6=0
the possible values of k are
k=-5. if x²+kx+6=0
k=-1 if x²+kx-6=0
k=5 if x²-kx+6=0
k=1 if x²-kx-6=0
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