Question

If x=3 is a solution of the equation 3×^2+(k-2)x +9=0 then k equals to

Answer 1

Answer:

Let's solve your equation step-by-step.

(3)(2)+(k−2)(3)+9=0

Step 1: Simplify both sides of the equation.

(3)(2)+(k−2)(3)+9=0

(3)(2)+(k)(3)+(−2)(3)+9=0(Distribute)

6+3k+−6+9=0

(3k)+(6+−6+9)=0(Combine Like Terms)

3k+9=0

3k+9=0

Step 2: Subtract 9 from both sides.

3k+9−9=0−9

3k=−9

k=-9/3

k=-3

Answer 2

Answer:

-10

Step-by-step explanation:

Putting x=3

3(3)(3) + (k-2)3 + 9 =0

27 + 3k - 6 + 9 = 0

3k + 30 = 0

3k = - 30

k = - 10