Math, asked by azhar03071998, 10 days ago

If x = 3 is a solution of the equation 3x2 + (k - 1)x + 9 = 0 then k = ?​

Answers

Answered by nihaaafrin1
3

Answer:

-4

Step-by-step explanation:

3 × 2 + (k - 1) x + 9 = 0

putting the value of x :-

6 + (k - 1 ) ×3 +9 = 0

6 + 3k - 3 + 9 = 0

12 + 3k = 0

3k = -12

k = -12 / 3

k = -4..

Answered by saam3058
2

Step-by-step explanation:

put the value of x in equation

3x3^2+(k-1) x3+9=0

3x9 +(k-1) x3 +9=0

27+ (k-1) x3+9=0

36+(k-1) x3=0

3k-3=-36

3k=-36+3

3k=-33

k=-11

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