Question

If x-3 is a zero of the polynomial f(x)-2x^2-5x-7a find the value of a [a-33/7]

Answer 1

Answer:

The given polynomial is p(x)=x4−2x3+3x2−ax+3a−7

Given that, the polynomial p(x) when divided by (x+1) leaves remainder 19

Therefore, p(−1)=19 (By Remainder theorem)

=>(−1)4−2×(−1)3+3(−1)2−(−1)a+3a−7=19

=>1+2+3+a+3a−7=19

=>4a−1=19

=>4a=20

=>a=5

The value of a is 5

Now,

p(x)=x4−2x3+3x2−5x+3×5−7

        =x4−2x3+3x2−5x+15−7

        =x4−2x3+3x2−5x+8

Remainder when the polynomial is divided by (x+2)

               =p(−2)    (By Remainder Theorem)

               =−24−

Step-by-step explanation:

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