If X=3 is a zero of the polynomial x square-6x+6x+k find the value of k
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The question is xsquare-6x square+6x+k find k value
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Hey there !
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Given :
x = 3 is the zero of the polynomial x² - 6x² + 6x + + k.
To find :
Value of k.
Solution :
-------------
Let p(x) = x² - 6x² + 6x + k.
g(x) = x = 3
==> Putting the value of x = 3 in the given polynomial.
=> x² - 6x² + 6x + k = 0
=> 3² - 6 (3)² + 6 × 3 + k = 0
=> 9 - 6 × 9 + 18 + k = 0
=> 9 - 54 + 18 + k = 0
=> 9 - 36 + k = 0
=> -27 + k = 0
=> k = 27
.·. k = 27
Hence, the value of k is found.
The answer is k = 27.
________________________________
Thanks for the question!
________________________________
Given :
x = 3 is the zero of the polynomial x² - 6x² + 6x + + k.
To find :
Value of k.
Solution :
-------------
Let p(x) = x² - 6x² + 6x + k.
g(x) = x = 3
==> Putting the value of x = 3 in the given polynomial.
=> x² - 6x² + 6x + k = 0
=> 3² - 6 (3)² + 6 × 3 + k = 0
=> 9 - 6 × 9 + 18 + k = 0
=> 9 - 54 + 18 + k = 0
=> 9 - 36 + k = 0
=> -27 + k = 0
=> k = 27
.·. k = 27
Hence, the value of k is found.
The answer is k = 27.
________________________________
Thanks for the question!
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