Question

If x-3 is one of the factor of xcube+2xsquare-ax-8.Then a=?​

Answer 1

Answer:

x-3=0

x=3

(x)³+2(x)²-ax-8=0

(3)³+2(3)²-a*3-8=0

27+2(9)-3a-8=0

27+18-3a-8=0

45-8-3a=0

37-3a=0

37=3a

37/3=a