Question

if X + 3 is one of the factors of xcube + 2 X square + ax- 18 then a is equals to​

Answer 1

Given: x+3 is one of the factors of x³+2x²-ax-18.

To find: The value of a.

Solution:

• x³+2x²-ax-18 and x+3 are exponential terms and are divided using the long division method.
• Since x+3 is a factor of x³+2x²-ax-18, the remainder obtained from the division must be equal to zero.
• On dividing x³+2x²-ax-18 by x+3, the remainder obtained is -18-3(3-a).

• On equating it to zero, the equation obtained is,

        $-18-3(3-a) = 0$

• On rearranging and solving further, the value of a is found to be,

        $3a - 27 = 0$

         $a = 9$

Therefore, the value of a equals 9.

Answer 2

Answer:

If(x+3) is one of factor of x³+2x²-ax-18,then a= 9

Ans: 9