Math, asked by minnafathima4444, 1 year ago

If x=3 is one of the root of the equation x2_2kx_6=0, find the value of k?

Answers

Answered by shreya9960
1

this is the answer you require

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Answered by harjotsinghbhinder13
0
Solution==>

p(x)=x²-2kx-6=0

given x=3

so, put values of x in p(x)

(3)²-2k(3)-6=0

9-6k-6=0

-6k=-9+6

-6k=-3

k=-3/-6

k=1/2

•.• value of k is =1/2
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