if x=3 is one root of quadratic equation of x2-2kr-6 then find the value of k
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Answered by
4
it's wrong question
it's not r it's x
k = 1/2
it's not r it's x
k = 1/2
Answered by
8
Hey... I think this can be ur answer!!
Zero =3
Polynomial - x2 - 2kx - 6=0
Now,
P(3) = (3)2 - 2(3)k =6
=9 - 6k =6
= - 6k=-3
=k=1/2...
Hope it helps you dear ☺️☺️
Zero =3
Polynomial - x2 - 2kx - 6=0
Now,
P(3) = (3)2 - 2(3)k =6
=9 - 6k =6
= - 6k=-3
=k=1/2...
Hope it helps you dear ☺️☺️
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