Question

If x = 3 is one root of square the eq x²-2kx-6=0 the find the value of k

Answer 1

Given that x= 3 is the root of the equation x² - 2kx - 6 =0

Substituting x= 3 in the equation, we get:

3² - 6k - 6 = 0
⇒ 9 - 6 - 6k = 0
⇒ 3 = 6k
⇒ k = 3/6
⇒ k = 1/2

Answer 2

Hope this may help you friend

Here $x^{2} - 2kx-6 = 0$

As it is given that x = 3 so we will put x = 3 in the following equation

$P(3) = 3^{2} - 2k(3) - 6$

$P(3) = 9 -6k - 6$

$-3 = -6k$

$K = \frac{1}{y2}$

Hence the value of k = $K = \frac{1}{y2}$