Question

if x=3 is one root of the q.e x2-2kx-6=0,then find te value of k

Answer 1

hello friend your answer is
x=3
x²-2kx-6
3²-2k×3-6=0
9-6k-6=0
3-6k=0
k=1/2

Answer 2

x² -2kx -6=0

Put the value of x,

3² -2k*6 -6=0

9-6k -6 =0

9-6-6k=0

3-6k=0

3=6k

3/6 =k

1/2 =k


I hope this will help you


-by ABHAY