If x = 3 is one root of the quadirate equation x2 - 2 x r -6 = 0 than find the value of k
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2x-2xk-6=0
X=3
k=??
2(3)-2(3)k-6=0
6-6k-6=0
-6k=0
k=0/-6
k=0
this is your answer...
X=3
k=??
2(3)-2(3)k-6=0
6-6k-6=0
-6k=0
k=0/-6
k=0
this is your answer...
sunny548:
tnx
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