Question

if x=3 is one root of the quadratic eqn x2-2kx-6=0,then find the value of k

Answer 1

x = 3
then
$x { }^{2} - 2kx - 6 = 0$

so
$(3) {}^{2} - 6k - 6 = 0$
9-6-6k = 0
3= 6k
k = 3/6
k = 1/2

Answer 2

Hey friend...
x=3
& x^2 -2kx-6=0
Putting x=3 in given quadratic equation...
_________________________________________
=>(3)^2 -2(3)k-6=0
=> 9 -6k -6 =0
=> 3 -6k =0
=> -6k = -3
=> k = 1/2
So,the value of k is 1/2

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