if x = 3 is one root of the quadratic equation X 2 - 2 kx - 6 = 0
then find the value of k
Answers
Answered by
8
Hello friend your answer is
put x=3
x²-2kx-6=0
3²-2×k×3-6
9-6k-6
3-6k
-6k=-3
k=3/6=1/2
put x=3
x²-2kx-6=0
3²-2×k×3-6
9-6k-6
3-6k
-6k=-3
k=3/6=1/2
Answered by
8
Hi!
Here's the answer of your question>>>>>>>>
x2-2kx-6=0
(3)2-2k×3-6=0 (Given that x=3)
9-6k=6
9-6=6k
3=6k
1/2=k
HOPE this will help you............
Please mark it as brainliest.......................
Here's the answer of your question>>>>>>>>
x2-2kx-6=0
(3)2-2k×3-6=0 (Given that x=3)
9-6k=6
9-6=6k
3=6k
1/2=k
HOPE this will help you............
Please mark it as brainliest.......................
PrincessNancy:
Thanks for marking my answer as brainliest
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