Question

if x=3 is One root of the quadratic equation x^2-2kx-6=0, then find the value of k. ​

Answer 1

Step-by-step explanation:

x^2 - 2kx - 6 = 0

= 3^2 - 2k*3 - 6 = 0. (x=3)

= 9 - 6k - 6=0

= 3 - 6k = 0

= k= -3/-6

= k= 1/2 (ans.)

Answer 2

SOLUTION ☺️

Given,

x= 3

So, put the value of x in Quadratic eq^n.

=) x^2-2kx-6=0

=) (3)^2-2k(3)-6=0

=) 9-6k-6=0

=) -6k+3=0

=) -6k= -3

=) k= -3/-6

=) k= 1/2 [ANSWER]

hope it helps ✔️