Question

if x=3 is one root of the quadratic equation x^2-2kx-6=0 then find the value of x

Answer 1

x = 3

x2-2kx-6 = 0
(3)2 - 2(k)(3) - 6 =0
9 - 6k - 6 = 0
3 = 6k
k = 3/6 = 1/2

Maybe you are mistaken.. we have to find k not x

Hope this helps!!
cheers!! (:

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Answer 2

♧♧HERE IS YOUR ANSWER♧♧

Since, x = 3 is a root of x²-2kx-6=0, x = 3 is satisfies the equation.

So,

3² - 2×k×3 - 6 = 0

=> 9 - 6k - 6 = 0

=> 6k = 3

=> k = 1/2

So the value of k is 1/2.

♧♧HOPE IT HELPS YOU♧♧