Question

if x=3 is one root of the quadratic equation x^2-2kx-6=0 then find the value of k

Answer 1

<br> substituting the value of x in the equation, (3)^2 - 2(3) k - 6 = 0 9-6k-6=0 3 - 6k = 0 6k = 3 K = 1/2

Answer 2

X = 3


P ( x ) = x2 - 2kx - 6 = 0



=> (3)² - 2k × 3 - 6 = 0



=> 9 - 6k - 6 = 0



=> -6k + 3 = 0


=> -6k = -3


=> k = 1/2