Question

if x=3 is one root of the quadratic equation x^-2kx-6=0.then find the value of k

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$here \: {x}^{2} - 2kx - 6 = 0 \\ and \: x = \: 3 \\ by \: putting \: the \: value \: of \: x \: we \: get$

${3}^{2} - 2(3)k - 6 = 0 \\ 9 - 6k - 6 = 0$

$3 - 6k = 0 \\ - 6k = - 3 \\ k = \frac{3}{6} \\ k = \frac{1}{2}$

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