If x=3 is one root of the quadratic equation x2 -2kx-6=0 ,find the value of k
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Hey friend your answer is
If x=3 then
x²-2kx-6=0
3²-2k×3-6=0
9-6k-6=0
3-6k=0
-6k=-3
k=3/6=1/2
If x=3 then
x²-2kx-6=0
3²-2k×3-6=0
9-6k-6=0
3-6k=0
-6k=-3
k=3/6=1/2
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