Question

If x=3 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.​

Answer 1

Step-by-step explanation:

Let

p(x) = x²-2kx-6=0

x= 3 is one root of the quadratic equation

Remainder = p(3) = 0

=> p(3)=0

=> (3)²-2k(3) - 6 = 0

=> - 6k = -3

=> k=3/6

=> k=1/2

Answer 2

Answer:

put 3 in place of x

(3)²-2k(3)-6=0

9-6k-6=0

-6k=0-3

k=-3/6

k=-1/2

Step-by-step explanation:

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