if x=3 is one root of the quadratic equation x²-2kx-6=0,then find the value of k .
Answers
Answered by
8
HELLO!!!!
=========================================
x^2-2kx-6=0
Here x = 3....
So,(3)^2-2k(3)-6 =0
9-6k-6 =0
3 - 6k =0
-6k = -3
k = 1/2
=========================================
HOPE IT HELPS U✌✌✌
=========================================
x^2-2kx-6=0
Here x = 3....
So,(3)^2-2k(3)-6 =0
9-6k-6 =0
3 - 6k =0
-6k = -3
k = 1/2
=========================================
HOPE IT HELPS U✌✌✌
Answered by
3
value of k is 1/2.
x2-2kx-6=0
x=3 is the root is given.
putting the value of x in the equation.
9-6k-6=0
3-6k=0
-6k=-3
k=1/2
answer= 1/2
x2-2kx-6=0
x=3 is the root is given.
putting the value of x in the equation.
9-6k-6=0
3-6k=0
-6k=-3
k=1/2
answer= 1/2
Similar questions
English,
7 months ago
Economy,
7 months ago
India Languages,
1 year ago
Science,
1 year ago
English,
1 year ago