if x=3 is one root of the quadratic equation x2-2kx-6=0 then find the value of k.
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k=0is the answer.substitute in the equation x value.u get it
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f(x)=x²-2kx-6=0
f(3)=(3)²-2k*3 -6=0
=9-6k-6=0
=3-6k=0
=-6k =-3
k =1/2
f(3)=(3)²-2k*3 -6=0
=9-6k-6=0
=3-6k=0
=-6k =-3
k =1/2
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