Question

if x=3 is one root of the quadratic equation x2-2kx-6=o then find the value of k

Answer 1

Step-by-step explanation:

p(x)=x2-2kx-6=o

and x=3 is the zero of p(x) then,

p(3)=(3)^2-2k(3)-6=0

9-6k-6=0

3-6k=0

3(1-2k)=0

1-2k=0

-2k= -1

k=1

k=1 2