if x=3 is one root of the quardatic equation x-2k-6=0 find the value of k
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Hey.. I think this can be ur answer!!
Polynomial - x2 - 2kx - 6 =0
P(3) = (3)2 - 2(3)k =6
=9-6k=6
=-6k=-3
=k=1/2
Hope it helps you dear ☺️☺️☺️
Polynomial - x2 - 2kx - 6 =0
P(3) = (3)2 - 2(3)k =6
=9-6k=6
=-6k=-3
=k=1/2
Hope it helps you dear ☺️☺️☺️
paryan659:
thanks bro
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