If x=3 is one root of thr quadratic equation x^2-2x-6=0 then find the value of k.
HarishAS:
Where is the k in the equation??
Answers
Answered by
0
As x=3 is the answer to it so
Putting it in the eq we get
3×3 - 2k ×3-6 =0
9-6k-6=0
3-6k =0
3=6k
K=1/2
Mark as brainliest if its helpful
Putting it in the eq we get
3×3 - 2k ×3-6 =0
9-6k-6=0
3-6k =0
3=6k
K=1/2
Mark as brainliest if its helpful
Answered by
1
Hey friend, Harish here.
Here is your answer:
Given ,
1) An polynomial x² - 2kx -6 = f(x).
2) x = 3 is a factor,
To find,
The value of k.
Solution,
As x =3 is a factor , then if we substitute x = 3 we get, f(x) = 0.
Then,
f(3) = 3² - 2 k (3) - 6 =0
9 - 6k -6 =0
6k = 3.
k = 1/2.
_________________________________________________
Hope my answer is helpful to you.
Here is your answer:
Given ,
1) An polynomial x² - 2kx -6 = f(x).
2) x = 3 is a factor,
To find,
The value of k.
Solution,
As x =3 is a factor , then if we substitute x = 3 we get, f(x) = 0.
Then,
f(3) = 3² - 2 k (3) - 6 =0
9 - 6k -6 =0
6k = 3.
k = 1/2.
_________________________________________________
Hope my answer is helpful to you.
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