If x=3 is one roots of the quadratic equation (x)2-2k-6=0 then find value k
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Answered by
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Hey... I think this can be ur answer!!
Polynomial - x2 - 2kx - 6 =0
P (3)=(3)2 - 2(3)k =6
=9 - 6k =6
=-6k =-3
=k =1/2
Hope it helps you dear ☺️☺️
Polynomial - x2 - 2kx - 6 =0
P (3)=(3)2 - 2(3)k =6
=9 - 6k =6
=-6k =-3
=k =1/2
Hope it helps you dear ☺️☺️
athivjlijaykumar:
poyindi bro
Answered by
2
Mistake in your question.
Question:
If x = 3 is one roots of the quadratic equation then find value k.
Answer:
The value of k is .
Solution:
Given quadratic equation is .
(x – 3) is one root of the given quadratic equation.
Factor theorem:
A polynomial f(x) has a root (x – a), then f(a) = 0.
By factor theorem,
x – 3 = 0
x = 3
Substitute x = 3 in quadratic equation.
Subtract 9 from both sides of the equation.
Divide by –6 on both sides of the equation.
The value of k is .
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