if x = 3 is root of square .Area of x square - 2kr -6 =0. find the value of k
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p(x)=x^2-2kx-6=0
p(3)=3^2-6k-6=0
=9-6-6k=0
=3-6k=0
6k=3
=1/2
p(3)=3^2-6k-6=0
=9-6-6k=0
=3-6k=0
6k=3
=1/2
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