If x=3 is root of the quadratic equations x2 -2kx-6 =0 then find value of k
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Answered by
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3^2_2*k3_6=0
9_6k-6=0k=1/2
9_6k-6=0k=1/2
Answered by
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Let P(x)= x2-2kx-6=0
substitute x=3 in p(x) we get ;
=) (3)2 -2k(3)-6=0
=) 9-6k-6=0
=) 3-6k=0
=) -6k=-3
=) k=3/6
=)k=1/2
substitute x=3 in p(x) we get ;
=) (3)2 -2k(3)-6=0
=) 9-6k-6=0
=) 3-6k=0
=) -6k=-3
=) k=3/6
=)k=1/2
Ajal:
Thank you fair lovely
No
This is not a right questions
This is a simple question
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